Rearrange the digits in ⟨125034⟩ to meet the rules below.
⟨5th 4th 3rd 2nd 1st 0th⟩
✅Match
⟨⋯ a ⋯ 1 ⋯⟩, a = 2|5
⟨ ⁴ᵗʰa ³ʳᵈb ⁰ᵗʰc ⟩, (abc)₁₀ ≥ 123
⟨ − ▧ ▧ ▢ ▢ − ⟩, Σ▧ ≤ Σ▢
⛔Avoid
⟨ ⁴ᵗʰa ¹ˢᵗb ⟩, (ab)₁₀ ≥ 14
⟨ − ▧ ▧ ▢ − − ⟩, Σ▧ ≤ ▢
⟨⋯ 2 ⋯ 3 ⋯⟩
#125034_v2.10
┌───┬───┬───┬───┬───┬───┐ │5th│4th│3rd│2nd│1st│0th│▒ ╞═══╪═══╪═══╪═══╪═══╪═══╡▒ Step 1 │ │ 1 │ │ │ │ │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 2 │ │ 1 │ │ │ 2 │ │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 3 │ 5 │ 1 │ │ │ 2 │ │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 4 │ 5 │ 1 │ │ │ 2 │ 0 │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 5 │ 5 │ 1 │ 4 │ │ 2 │ 0 │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 6 │ 5 │ 1 │ 4 │ 3 │ 2 │ 0 │▒ └───┴───┴───┴───┴───┴───┘▒ ▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒ Proof of 2025-08-26 WR ══════════════════════ To avoid ⛔「⟨ ⁴ᵗʰa ¹ˢᵗb ⟩, (ab)₁₀ ≥ 14」, we need [4th] = 1 or 0. If it is 0, then we cannot match ✅「⟨ ⁴ᵗʰa ³ʳᵈb ⁰ᵗʰc ⟩, (abc)₁₀ ≥ 123」. Therefore, [4th] = 1. ┌───┬───┬───┬───┬───┬───┐ │5th│ 4■│3rd│2nd│1st│0th│▒ ╞═══╪═══╪═══╪═══╪═══╪═══╡▒ Step 1 │ │ 1 │ │ │ │ │▒ └───┴───┴───┴───┴───┴───┘▒ ▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒ --- Idle --- ┌───┬───┬───┬───┬───┬───┐ │ │ 2 │ 5 │ 0 │ 3 │ 4 │ └───┴───┴───┴───┴───┴───┘ Then, to avoid ⛔「⟨ ⁴ᵗʰa ¹ˢᵗb ⟩, (ab)₁₀ ≥ 14」, we need (1) [1st] = 0,2,3. ┌───┬───┬───┬───┬───┬───┐ │5th│4th│3rd│2nd│1st│0th│ ╞═══╪═══╪═══╪═══╪═══╪═══╡ │ │ 1 │ │ │ ▬ │ │ └───┴───┴───┴───┴───┴───┘ (1.1) We show that [1st] = 2 actually. ------------------------------ (2.1) Note that if [1st] = 0: ┌───┬───┬───┬───┬───┬───┐ │5th│4th│3rd│2nd│ 1▲│0th│ ╞═══╪═══╪═══╪═══╪═══╪═══╡ │ │ 1 │ │ │ 0 │ │ └───┴───┴───┴───┴───┴───┘ then we cannot match ✅「⟨ − ▧ ▧ ▢ ▢ − ⟩, Σ▧ ≤ Σ▢」 and avoid ⛔「⟨ − ▧ ▧ ▢ − − ⟩, Σ▧ ≤ ▢」 at the same time. This shows a contradiction. (2.2) Else if [1st] = 3: ┌───┬───┬───┬───┬───┬───┐ │5th│4th│3rd│2nd│ 1▲│0th│ ╞═══╪═══╪═══╪═══╪═══╪═══╡ │ │ 1 │ │ │ 3 │ │ └───┴───┴───┴───┴───┴───┘ then to avoid ⛔「⟨⋯ 2 ⋯ 3 ⋯⟩」, we need 2 = [0th]: ┌───┬───┬───┬───┬───┬───┐ │5th│4th│3rd│2nd│1st│ 0▲│ ╞═══╪═══╪═══╪═══╪═══╪═══╡ │ │ 1 │ │ │ 3 │ 2 │ └───┴───┴───┴───┴───┴───┘ It follows that to match ✅「⟨⋯ a ⋯ 1 ⋯⟩, a = 2|5」, we need [5th] = 5: ┌───┬───┬───┬───┬───┬───┐ │ 5▲│4th│3rd│2nd│1st│0th│ ╞═══╪═══╪═══╪═══╪═══╪═══╡ │ 5 │ 1 │ │ │ 3 │ 2 │ └───┴───┴───┴───┴───┴───┘ --- Idle --- ┌───┬───┬───┬───┬───┬───┐ │ │ │ │ 0 │ │ 4 │ └───┴───┴───┴───┴───┴───┘ In view of ✅「⟨ ⁴ᵗʰa ³ʳᵈb ⁰ᵗʰc ⟩, (abc)₁₀ ≥ 123」, we reach ┌───┬───┬───┬───┬───┬───┐ │5th│4th│ 3▲│ 2▲│1st│0th│ ╞═══╪═══╪═══╪═══╪═══╪═══╡ │ 5 │ 1 │ 4 │ 0 │ 3 │ 2 │ └───┴───┴───┴───┴───┴───┘ However, it fails to match ✅「⟨ − ▧ ▧ ▢ ▢ − ⟩, Σ▧ ≤ Σ▢」, which shows a contradiction. ------------------------------ We have verified (1.1). Accordingly, we get ┌───┬───┬───┬───┬───┬───┐ │5th│4th│3rd│2nd│ 1■│0th│▒ ╞═══╪═══╪═══╪═══╪═══╪═══╡▒ │ │ 1 │ │ │ │ │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 2 │ │ 1 │ │ │ 2 │ │▒ └───┴───┴───┴───┴───┴───┘▒ ▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒ --- Idle --- ┌───┬───┬───┬───┬───┬───┐ │ │ │ 5 │ 0 │ 3 │ 4 │ └───┴───┴───┴───┴───┴───┘ Then, there is only one way to match ✅「⟨⋯ a ⋯ 1 ⋯⟩, a = 2|5」: ┌───┬───┬───┬───┬───┬───┐ │ 5■│4th│3rd│2nd│1st│0th│▒ ╞═══╪═══╪═══╪═══╪═══╪═══╡▒ │ │ 1 │ │ │ 2 │ │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 3 │ 5 │ 1 │ │ │ 2 │ │▒ └───┴───┴───┴───┴───┴───┘▒ ▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒ --- Idle --- ┌───┬───┬───┬───┬───┬───┐ │ │ │ │ 0 │ 3 │ 4 │ └───┴───┴───┴───┴───┴───┘ Next, we consider where to place 0. Note that if it is at 2nd: ┌───┬───┬───┬───┬───┬───┐ │5th│4th│3rd│ 2▲│1st│0th│ ╞═══╪═══╪═══╪═══╪═══╪═══╡ │ 5 │ 1 │ │ 0 │ 2 │ │ └───┴───┴───┴───┴───┴───┘ --- Idle --- ┌───┬───┬───┬───┬───┬───┐ │ │ │ │ │ 3 │ 4 │ └───┴───┴───┴───┴───┴───┘ then we would fail to match ✅「⟨ − ▧ ▧ ▢ ▢ − ⟩, Σ▧ ≤ Σ▢」. On the other hand, by ✅「⟨ ⁴ᵗʰa ³ʳᵈb ⁰ᵗʰc ⟩, (abc)₁₀ ≥ 123」, 0 is not at 3rd. Therefore, 0 = [0th]: ┌───┬───┬───┬───┬───┬───┐ │5th│4th│3rd│2nd│1st│ 0■│▒ ╞═══╪═══╪═══╪═══╪═══╪═══╡▒ │ 5 │ 1 │ │ │ 2 │ │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 4 │ 5 │ 1 │ │ │ 2 │ 0 │▒ └───┴───┴───┴───┴───┴───┘▒ ▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒ --- Idle --- ┌───┬───┬───┬───┬───┬───┐ │ │ │ │ │ 3 │ 4 │ └───┴───┴───┴───┴───┴───┘ Finally, to avoid ⛔「⟨ − ▧ ▧ ▢ − − ⟩, Σ▧ ≤ ▢」, we finish by ┌───┬───┬───┬───┬───┬───┐ │5th│4th│ 3■│ 2■│1st│0th│▒ ╞═══╪═══╪═══╪═══╪═══╪═══╡▒ │ 5 │ 1 │ │ │ 2 │ 0 │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 5 │ 5 │ 1 │ 4 │ │ 2 │ 0 │▒ ├───┼───┼───┼───┼───┼───┤▒ Step 6 │ 5 │ 1 │ 4 │ 3 │ 2 │ 0 │▒ └───┴───┴───┴───┴───┴───┘▒ ▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒ --- Idle --- ┌───┬───┬───┬───┬───┬───┐ │ │ │ │ │ │ │ └───┴───┴───┴───┴───┴───┘ Q.E.D. #125034_v2.10